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Explanation & Answer
Attached.
46. Radiation energy form the sun is absorbed 30kcal/hr = 34.9W
TAIR = 30 degrees C = 303 degrees K
TSKIN = 32 degrees C = 305 degrees K
Area = 0.9 m2
a) Rate of radiation energy:
4
4
𝑃 = 𝜎𝐴(𝑇𝑆𝐾𝐼𝑁
− 𝑇𝐴𝐼𝑅
)
−8
𝜎 = 5.6703 × 10 𝑤/𝑚2 𝑘 4
𝑃 = 5.67 × 10−8 × 0.9[(305)4 − (303)4 ] ≈ 11.4W
So, Net energy is 32.9𝑊 − 11.4𝑊 = 23.5 ≈ 24𝑊
T...