MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php Assignment 2.2 Name: Haddy Badjie #1 Points possible: 1. Total attempts: 3 Let f(x) = 2√x If g(x) is the graph of f(x) shifted up 2 units and right 6 units, write a formula for g(x) g(x)= 2sqrt(x) +6-4 Enter √x as sqrt(x) #2 Points possible: 1. Total attempts: 3 5 4 3 2 1 -5 -4 -3 -2 -1 -1 1 2 3 4 5 -2 -3 -4 -5 The graph above is the graph of: y = |x − 3| − 2 y = |x − 2| − 3 y = |x + 3| − 2 1 of 10 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #3 Points possible: 1. Total attempts: 1 5 4 3 2 1 -5 -4 -3 -2 -1 -1 1 2 3 4 5 -2 -3 -4 -5 Complete an equation for the function graphed above y= Enter abs(x) for |x| 2 of 10 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #4 Points possible: 1. Total attempts: 3 The graph of y = √x is given below: 5 4 3 2 1 -5 -4 -3 -2 -1 -1 1 2 3 4 5 -2 -3 -4 -5 Find a formula for each of the transformations whose graphs are given below. Recall that square root is entered as sqrt. a) 5 4 3 2 1 -5 -4 -3 -2 -1 -1 1 2 3 4 5 1 2 3 4 5 -2 -3 -4 -5 y= b) 5 4 3 2 1 -5 -4 -3 -2 -1 -1 -2 -3 -4 -5 y= 3 of 10 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #5 Points possible: 1. Total attempts: 3 6 5 4 3 2 1 -6 -5 -4 -3 -2 -1 -1 1 2 3 4 5 6 -2 -3 -4 -5 -6 The graph above is a transformation of the function x2 Write an equation for the function graphed above g(x) = 4 of 10 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #6 Points possible: 1. Total attempts: 1 Match the function with its graph. 2 y = 3(x + 2) − 3 6 6 5 5 4 4 3 3 2 2 1 1 -6 -5 -4 -3 -2 -1 -1 2 3 4 5 6 -6 -5 -4 -3 -2 -1 -1 -2 -2 -3 -3 -4 -4 -5 -5 -6 -6 6 6 5 5 4 4 3 3 2 2 1 1 -6 -5 -4 -3 -2 -1 -1 5 of 10 1 1 2 3 4 5 6 -6 -5 -4 -3 -2 -1 -1 -2 -2 -3 -3 -4 -4 -5 -5 -6 -6 1 2 3 4 5 6 1 2 3 4 5 6 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #7 Points possible: 1. Total attempts: 3 6 5 4 3 2 1 -6 -5 -4 -3 -2 -1 -1 1 2 3 4 5 6 -2 -3 -4 -5 -6 The graph above is a transformation of the function x2 Write an equation for the function graphed above g(x) = #8 Points possible: 1. Total attempts: 3 6 5 4 3 2 1 -6 -5 -4 -3 -2 -1 -1 1 2 3 4 5 6 -2 -3 -4 -5 -6 The graph above is a transformation of the function f(x) = |x| Write an equation for the function graphed above g(x) = 6 of 10 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #9 Points possible: 1. Total attempts: 3 Sketch a graph of f(x) = 1 |x + 4| − 1 2 #10 Points possible: 1. Total attempts: 3 Sketch a graph of f(x) = − 7 of 10 1 2 (x + 1) + 3 2 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #11 Points possible: 1. Total attempts: 3 Given the function 8x − 6 x < 0 f(x) = { 8x − 12 x ≥ 0 Calculate the following values: f( − 1) = f(0) = f(2) = #12 Points possible: 1. Total attempts: 3 Given the function 1x2 + 4 x < 1 f(x) = { 2 2x + 4 x ≥ 1 Calculate the following values: f( − 2) = f(1) = f(2) = #13 Points possible: 1. Total attempts: 3 Complete the equation for the piecewise function graphed below. 6 5 4 3 2 1 -7 -6 -5 -4 -3 -2 -1 -1 1 2 3 4 5 6 7 -2 -3 -4 -5 -6 { f(x) = { { 8 of 10 if − 6 ≤ x ≤ − 2 if − 2 < x ≤ 3 if 3 < x ≤ 6 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #14 Points possible: 1. Total attempts: 3 if x ≤ − 1 ⎧ ⎪ −2 Sketch a graph of f(x) = ⎨ x − 1 if − 1 < x ≤ 2 ⎩ ⎪ −1 if x > 2 Notes: Only use dots at if two parts of the function don't connect. Once you draw a line segment, click outside the graph if you need to end the line. 9 of 10 2/24/20, 3:27 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php #15 Points possible: 1. Total attempts: 3 ⎧ ⎪ − 2 if x ≤ − 1 Sketch a graph of f(x) = ⎨ x if − 1 < x ≤ 2 ⎩ ⎪ 4 if x > 2 Note: Be sure to include closed or open dots as needed 10 of 10 2/24/20, 3:27 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.4.html Assignment 2.4 Name: Haddy Badjie #1 Points possible: 1. Total attempts: 3 A bank features a savings account that has an annual percentage rate of r = 5.1% with interest compounded quarterly. April deposits $8,000 into the account. r nt ) , where A is n account value after t years , a is the principal (starting amount), r is the annual percentage rate, k is the number of times each year that the interest is compounded. The account balance can be modeled by the exponential formula A(t) = a(1 + (A) What values should be used for a, r, and n? a= , r= , n= (B) How much money will April have in the account in 8 years? Answer = $ . Round answer to the nearest penny. (C) What is the annual percentage yield (APY) for the savings account? (The APY is the actual or effective annual percentage rate which includes all compounding in the year). AP Y = %. Round answer to 3 decimal places. File failed to load: file:///Users/Jahou/Desktop/Assignment%202.4_files/extensions/MathZoom.js 1 of 7 2/26/20, 10:55 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.4.html #2 Points possible: 1. Total attempts: 3 R K G B O Match each equation with a graph above x a. red (R) x b. green (G) x c. blue (B) x d. orange (O) x e. black (K) - 3(0.67) - 3(0.88) - 2(1.26) - 3(1.26) - 3(1.43) #3 Points possible: 1. Total attempts: 3 O B K G R If all the graphs above have equations with form y = abx , Which graph has the largest value for b? Which graph has the smallest value for b? Which graph has the largest value for a? Select an answer Select an answer Select an answer File failed to load: file:///Users/Jahou/Desktop/Assignment%202.4_files/extensions/MathZoom.js 2 of 7 2/26/20, 10:55 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.4.html #4 Points possible: 1. Total attempts: 3 The function below has the form f(x) = bx + k. 7 6 5 4 3 2 1 -5 -4 -3 -2 -1 -1 1 2 3 4 5 -2 -3 -4 -5 -6 -7 -8 Which of the following functions is shown on the graph? f(x) = 3x + 3 1 x f(x) = ( ) − 2 3 f(x) = 3x − 3 1 x f(x) = ( ) − 4 3 f(x) = 3x − 4 1 x f(x) = ( ) + 3 3 f(x) = 3x − 2 1 x f(x) = ( ) − 3 3 File failed to load: file:///Users/Jahou/Desktop/Assignment%202.4_files/extensions/MathZoom.js 3 of 7 2/26/20, 10:55 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.4.html #5 Points possible: 1. Total attempts: 3 The table below shows values from the function f(x) = bx . Identify b. x -2 -1 0 1 2 f(x) 4 2 1 1 2 1 4 b= File failed to load: file:///Users/Jahou/Desktop/Assignment%202.4_files/extensions/MathZoom.js 4 of 7 2/26/20, 10:55 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.4.html #6 Points possible: 1. Total attempts: 3 What function is graphed below? 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 -5 -4 -3 -2 -1 -1 1 2 3 4 5 -2 -3 -4 -5 f(x) = 3x 1 x f(x) = ( ) 5 1 x f(x) = ( ) 2 f(x) = 2x 1 x f(x) = ( ) 4 f(x) = 4x 1 x f(x) = ( ) 3 f(x) = 5x File failed to load: file:///Users/Jahou/Desktop/Assignment%202.4_files/extensions/MathZoom.js 5 of 7 2/26/20, 10:55 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.4.html #7 Points possible: 1. Total attempts: 3 Graphing Exponential Functions x Graph the Exponential Function f(x) = 4(4) by plotting the Vertical Intercept and one other point. Then write the Vertical Intercept as an ordered pair. Graph the function x f(x) = 4(4) Identify the Vertical Intercept as an Ordered Pair File failed to load: file:///Users/Jahou/Desktop/Assignment%202.4_files/extensions/MathZoom.js 6 of 7 2/26/20, 10:55 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.4.html #8 Points possible: 1. Total attempts: 3 Draw the graph of f(x) = 5x − 3 #9 Points possible: 1. Total attempts: 3 Use the like-bases property and exponents to solve the equation 3n = 27 n= #10 Points possible: 1. Total attempts: 3 Solve for x: 4x − 5 = 8x + 2 x= #11 Points possible: 1. Total attempts: 3 Use the like-bases property and exponents to solve the equation n 7(5) − 19 = 4356 n= File failed to load: file:///Users/Jahou/Desktop/Assignment%202.4_files/extensions/MathZoom.js 7 of 7 2/26/20, 10:55 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.5.html Assignment 2.5 Name: Haddy Badjie #1 Points possible: 1. Total attempts: 3 Write the equation in exponential form. Assume that all constants are positive and not equal to 1. log(r) = w #2 Points possible: 1. Total attempts: 3 Write the equation in logarithmic form. Assume that all constants are positive and not equal to 1. 10z = y Hint #3 Points possible: 1. Total attempts: 3 Find the logarithm. log10 (1, 000)= #4 Points possible: 1. Total attempts: 3 Evaluate using your calculator, giving at least 3 decimal places: log(130) = #5 Points possible: 1. Total attempts: 3 Evaluate using your calculator and round to 4 decimal places. log13 72 = #6 Points possible: 1. Total attempts: 3 Evaluate using your calculator and round to 4 decimal places: log16 0.98 = File failed to load: file:///Users/Jahou/Desktop/Assignment%202.5_files/extensions/MathZoom.js 1 of 4 2/26/20, 10:56 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.5.html #7 Points possible: 1. Total attempts: 3 Find the domain of y = log(5 + 5x). The domain is: #8 Points possible: 1. Total attempts: 3 Use the Laws of logarithms to rewrite the expression x6 y 17 log( 12 ) z in a form with no logarithm of a product, quotient or power. After rewriting we have x6 y 17 log( 12 ) = A log(x) + B log(y) + C log(z) z with A= B= and C= #9 Points possible: 1. Total attempts: 3 Simplify. Enter the result as a single logarithm with a coefficient of 1. To enter the log, click in the answer cell, then click on the small yellow arrow on the right. Then click the Functions tab to access the log. If needed, you can change the base. x2 Using the keyboard, you can also enter log3 ( ) as log_3(x^2/2). 2 log7 (2x) − log7 (x7 ) = #10 Points possible: 1. Total attempts: 3 If ln(4x + 3) = 2, then x = . File failed to load: file:///Users/Jahou/Desktop/Assignment%202.5_files/extensions/MathZoom.js 2 of 4 2/26/20, 10:56 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.5.html #11 Points possible: 1. Total attempts: 3 Solve for x: log4 (x5 ) = − 9 x= #12 Points possible: 1. Total attempts: 3 Solve for x: log2 x + log2 (x + 4) = 7 x= #13 Points possible: 1. Total attempts: 3 Solve for x: 3x = 38 x= You may enter the exact value or round to 4 decimal places. #14 Points possible: 1. Total attempts: 3 If e3x = 14, then x = . #15 Points possible: 1. Total attempts: 3 The value of China's exports of automobiles and parts (in billions of dollars) is approximately v(x) = 1.8208e0.3387x , where x = 0 corresponds to 1998. In what year did/will the exports reach $7.2 billion? Give your answer as the year, with at least one decimal place File failed to load: file:///Users/Jahou/Desktop/Assignment%202.5_files/extensions/MathZoom.js 3 of 4 2/26/20, 10:56 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 2.5.html #16 Points possible: 1. Total attempts: 3 You deposit $2200 in an account earning 4% interest compounded monthly. How long will it take this investment to double? Round your answer to two decimal places. Use this compound r nt interest formula: A = P (1 + ) n About years File failed to load: file:///Users/Jahou/Desktop/Assignment%202.5_files/extensions/MathZoom.js 4 of 4 2/26/20, 10:56 PM MyOpenMath Assessment Assignment 3.1 file:///Users/Jahou/Desktop/Assignment 3.1 .html Name: Haddy Badjie #1 Points possible: 1. Total attempts: 3 Use the table to find lim f(x) x→8 x 7 7.9 7.99 8 8.01 8.1 9 f(x) 4 5.8 5.99 5 6.02 6.1 9 lim f(x) = x→8 File failed to load: file:///Users/Jahou/Desktop/Assignment%203.1%20_files/extensions/MathMenu.js 1 of 5 2/26/20, 10:56 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 3.1 .html #2 Points possible: 1. Total attempts: 3 Consider f(x) = x2 − 36 x−6 x f(x) x f(x) 5.9 11.9 6.1 12.1 5.99 6.01 5.999 6.001 5.9999 6.0001 Looking at the values, we can estimate that lim f(x) = x→6 #3 Points possible: 1. Total attempts: 3 The graph below is the function f(x) 5 4 3 2 1 -5 -4 -3 -2 -1 -1 1 2 3 4 5 -2 -3 -4 -5 Find Find lim f(x) lim f(x) x → − 1− x → − 1+ Find lim x→ −1 f(x) Find f( − 1) File failed to load: file:///Users/Jahou/Desktop/Assignment%203.1%20_files/extensions/MathMenu.js 2 of 5 2/26/20, 10:56 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 3.1 .html #4 Points possible: 1. Total attempts: 3 The graph below is the function f(x) 5 4 3 2 1 -5 -4 -3 -2 -1 -1 1 2 3 4 5 -2 -3 -4 -5 Find lim f(x) Find lim f(x) x → 2− x → 2+ Find lim x→2 f(x) Find f(2) File failed to load: file:///Users/Jahou/Desktop/Assignment%203.1%20_files/extensions/MathMenu.js 3 of 5 2/26/20, 10:56 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 3.1 .html #5 Points possible: 1. Total attempts: 3 Enter each answer as a whole number (like -4, 0, or 253) or DNE for undefined or Does Not Exist. f(2) = lim f(x) = lim f(x) = x → 2− x → 8+ lim x→1 f(x) = #6 Points possible: 1. Total attempts: 3 Evaluate the limit: lim x→9 x2 − 5x − 36 x−9 File failed to load: file:///Users/Jahou/Desktop/Assignment%203.1%20_files/extensions/MathMenu.js 4 of 5 2/26/20, 10:56 PM MyOpenMath Assessment file:///Users/Jahou/Desktop/Assignment 3.1 .html #7 Points possible: 1. Total attempts: 3 Evaluate the limit: lim x→ −1 x2 x+1 = − 4x − 5 #8 Points possible: 1. Total attempts: 3 4 − x − x2 if x ≤ 5 2x − 36 if x > 5 Calculate the following limits. Enter "DNE" if the limit does not exist. lim f(x) = Let f(x) = { x → 5− lim x → 5+ lim x→5 f(x) = f(x) = #9 Points possible: 1. Total attempts: 3 Let f(x) = { 4 − x − x2 if x ≤ 3 2x − 5 if x > 3 Use a graph to determine the following limits. Enter DNE if the limit does not exist. lim f(x) = lim f(x) = x → 3− x → 3+ lim x→3 f(x) = File failed to load: file:///Users/Jahou/Desktop/Assignment%203.1%20_files/extensions/MathMenu.js 5 of 5 2/26/20, 10:56 PM MyOpenMath Assessment https://www.myopenmath.com/assessment/printtest.php Assignment 2.3 Name: Haddy Badjie #1 Points possible: 1. Total attempts: 3 Consider the Quadratic function f(x) = 2x2 – 11x – 21. Its vertex is ( ); its largest x-intercept is x = its y-intercept is y = #2 Points possible: 1. Total attempts: 3 Consider the quadratic function f(x) = – 5x + 6. Determine the following: The smallest x-intercept is x = The largest x-intercept is x = The y-intercept is y #3 Points possible: 1. Total attempts: 3 Write an equation (any form) for the quadratic graphed below 5 41 -5 -4 3-2 3 4 -2 -3 -4 -5+ y = 1 of 5 2/24/20, 3:31 PM
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