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Solr123

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Statistics

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: Question:
(a) And (b)
We choose as a test statistic T, the sum of the chips
)(
21
XX +
.The critical region corresponds
to values T that are less than 5, so test is one-tailed. Each possible outcome consists of two
numbers from 1 to 12.
Thus, there are
1441212 =
points in the sample space. To decide which of these points to
include in the critical region, we will assume that Null Hypothesis
)(
0
H
is true and keep an eye
on
.
If null Hypothesis is true, the ranks of two chips should behave as a random sample of two ranks
out of 12 possible. Therefore, each selection of two ranks is equally likely.
So each point in the sample space has probability
144
1
=
As decided, it is single tailed test; we examine the points that correspond to low values of T. The
lowest possible value is 2. Other low values of T and their corresponding experimental outcomes
are given below:
There are 5 points that corresponds to values of
5T
. The critical region consists of all points
that correspond to values of
5T
.
035.0
144
5
==
Since all points in the sample space has equal probability under
.
T
Points
3
(1,2)
4
(1,3)
4
(2,2)
4
(3,1)

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: Question: (a) And (b) We choose as a test statistic T, the sum of the chips (X 1  X 2 ) .The critical region corresponds to values T that are less than 5, so test is one-tailed. Each possible outcome consists of two numbers from 1 to 12. Thus, there are 12  12  144 points in the sample space. To decide which of these points to include in the critical region, we will assume that Null Hypothesis (H 0 ) is true and keep an eye on  . If null Hypothesis is true, the ranks of two chips should behave as a random sample of two ranks out of 12 possible. Therefore, each selection of two ra ...
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Anonymous
Very useful material for studying!

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