Indiana University East Physics Worksheet

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Science

Indiana University East

Description

1- Jayden selects up a heavy barbell and

  1. Lifts it to chest height
  2. Holds it steady for 1 minute
  3. Puts it gently back on the floor.

Rank the amounts of work Jayden performs during this three operations.

Label the quantities as W1, W2, and W3. Justify your ranking order.


2-

Part A

Estimate the kinetic energy of your car as you are driving down the highway. (If you don’t own a car, you are helping the environment, in this case, estimate for someone else’s!) Of course, you will need to estimate values of the mass and velocity of the car. Explain these and any other assumptions you make.


3-

Part A

One farmer is bragging about how strong his horse is. Another farmer says that his horse is more powerful. How would you rephrase these statements using careful physics terminology? What is really the difference between the two horses?


4- Diego pulls a box along the floor using a rope. The rope makes a 30 degree angle with the horizontal, and he pulls with a force of 20 N. Over the course of 5 seconds, he drags the box 3 meters. How much work does Diego do on the box?


Explanation & Answer:
4 Problems
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Explanation & Answer

Please find attached all answers in PDF and doc format. Please note both files are exactly same content-wise. Please let me know, if any doubt.Thanks

1- Jayden selects up a heavy barbell and
1. Lifts it to chest height
2. Holds it steady for 1 minute
3. Puts it gently back on the floor.
Rank the amounts of work Jayden performs during thesethree operations.
Label the quantities as W1, W2, and W3. Justify your ranking order.
Answer:
Ranking of the amounts of work Jayden performs during these three operations:
𝑾𝟑 = 𝑾𝟏 > 𝑾𝟐
1. While lifting the barbell to the chest, the force applied by Jayden is weight of barbell (mg)
upward and displacement is up to chest height (let h) is also upward, so 𝑤𝑜𝑟𝑑 𝑑𝑜𝑛𝑒 =
𝑓𝑜𝑟𝑐𝑒 ∗ 𝑑𝑖𝑠𝑝𝑙𝑎𝑐𝑒𝑚𝑒𝑛𝑡 = 𝒎𝒈𝒉
2. While holding it steady, the force applied by Jayden is weight of barbell (mg), but
displacement = 0, so 𝑤𝑜𝑟𝑑 𝑑𝑜𝑛𝑒 = 𝑓𝑜𝑟𝑐𝑒 ∗ 𝑑𝑖𝑠𝑝𝑙𝑎𝑐𝑒𝑚𝑒𝑛𝑡 = 𝟎
3. While putting it back gently on floor, again the force applied will be again weight of barbell
(mg) upward and displacement is h downward, so 𝑤𝑜𝑟𝑑 𝑑𝑜𝑛𝑒 = 𝑓𝑜𝑟𝑐𝑒 ∗ 𝑑𝑖𝑠𝑝𝑙𝑎𝑐𝑒𝑚𝑒𝑛𝑡 =
𝑚𝑔 ∗ (−ℎ) = −𝒎𝒈𝒉
Here, we have compared the magnitude of work, so order is:
𝑾𝟑 = 𝑾𝟏 > 𝑾𝟐
2-PART A
Estimate the ki...


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