MAC 2313 - Calculus III - Worksheet 2
Name_________________________
Complete the worksheet on a separate sheet of paper. Solve each question below. The worksheet
worth 100 points. Show all work. Please print these pages and attach then, staple, to the
front of your work.
1. Given ! A = (1, 4,5 ) and ! B = ( 4,−2, 7 ) find: (a) the distance between the points ! A and ! B .
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(Aside: The same as ! AB .) (b) the vector ! AB . (c) the midpoint of the line segment ! AB .
2. Find the center and radius of the sphere ! x 2 + y 2 + z 2 − 6y + 8z = 0 .
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! ! !
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3. Given ! u = 2i + 2 j + k and ! v = 2i + 10 j − 11k find: (a) ! u ⋅ v , ! u , and ! v . (b) the angle between
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! u and ! v . (c) the vector ! projv! u . (d) the vector ! proju! v .
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! !
! !
4. Given ! u = 2,−2, 4 and ! v = 1,1,−2 , find: (a) the vector ! u × v . (b) the unit vector for ! v × u .
5. Find the line ! L1 , in Vector Form and Parametric Form, through the point ! ( 3,−2,1) and parallel
to the line ! L2 : ! x = 1+ 2t , ! y = 2 − t , ! z = 3t .
6. Find the line ! L , in Vector Form and Symmetric Form, through the point ! ( 2, 3,0 ) and
!
!
perpendicular to the vectors ! u = i + 2 j + 3k and ! v = 3i + 4 j + 5k .
7. Find the point of intersection of the lines ! L1 : ! x, y, z = 0,2,
! x, y, z =
3
+ t 2,−15,6 and ! L2 :
5
4 3 13
, ,
+ s 2, 4,2 .
3 2 5
8. Determine if the lines ! L1 : ! x, y, z = 2,0,−4 + t −3,1,0 and ! L2 :
! x, y, z = −2,0, 4 + s −1,0, 3 are parallel, intersecting, or skewed.
9. Find the plane ! P1 , in Linear Form, containing the point ! (1,−1, 3) and parallel to the plane ! P2
! 3x + y + z = 7 .
10. Find the plane ! P , in Linear Form, containing the points ! (1,1,−1) , ! ( 2,0,2 ) , and ! ( 0,−2,1) .
11. Find the plane ! P , in Linear Form, containing the points ! ( 0,0,0 ) , ! ( 0,−1,−1) , ! ( 2,0,−2 ) , and
⎛ 3 ⎞
! ⎜ 1, ,0 ⎟ . (Hint: Finding a plane requires at least three points.)
⎝ 4 ⎠
12. Find the line ! L of intersection and the angle ! θ of intersection of the planes ! P1 : ! −x + z =
2
3
1
5
and ! P2 : ! x − 2y + z = 4 .
2
2
13. Find the point of intersection of the lines ! L1 : ! x = 2t + 1 , ! y = 3t + 2 , ! z = 4t + 3 and ! L2 :
! x = s + 2 , ! y = 2s + 4 , ! z = −4s − 1 , and then find the plane ! P , in Linear Form, determined by
these lines. (Aside: The plane ! P containing the point of intersection and vectors parallel to each
line.)
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14. Find the natural domain of the space curve ! r ( t ) =
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15. Find the limit of the space curve ! r ( t ) = lim
t→∞
(
)
5 − t i + ( t + 1)
1/4
(
)
j + log 3 ( t 2 ) k .
3e2t − 1
t +1
1
1
,
,
+
t
2t
2 ( e − 2e ) t + 9t 2 − 1 t 2 − 1 t
!
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16. Given the space curve ! r ( t ) = e2t ,e−2t ,te2t , find ! T ( 0 ) , ! r '' ( 0 ) , and ! r ' ( t ) ⋅ r '' ( t ) .
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17. Find the tangent line to the space curve ! r ( t ) =
!
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18. Find the space curve ! r ( t ) , given that ! r ' ( t ) =
This is an explicit differential equation.)
3
2
t 2 + 3,ln ( t 2 + 3) ,t at the point ! ( 2,ln ( 4 ) ,1) .
(t + 1)
1
2
i + e −t j +
!
1
k and ! r ( 0 ) = k . (Aside:
t +1
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